题解 | #二分查找-I#
二分查找-I
https://www.nowcoder.com/practice/d3df40bd23594118b57554129cadf47b
# # 代码中的类名、方法名、参数名已经指定,请勿修改,直接返回方法规定的值即可 # # # @param nums int整型一维数组 # @param target int整型 # @return int整型 # class Solution: def search(self, nums: list, target: int) -> int: left = 0 right = len(nums) while left <= right and len(nums)!=0 : mid = int((left + right) // 2) print(mid,'mid值') if target == nums[mid]: return mid elif target > nums[mid]: left = mid + 1 print(left,'left值') else: right = mid - 1 print(right,'right值') return -1 two = Solution() nums = [] x = two.search(nums= nums,target=-1) print(x)#悬赏#