题解 | #比较版本号#

#
# 代码中的类名、方法名、参数名已经指定，请勿修改，直接返回方法规定的值即可
#
# 比较版本号
# @param version1 string字符串 
# @param version2 string字符串 
# @return int整型
#
class Solution:
    def compare(self , version1: str, version2: str) -> int:
        v1 = version1.split(".")
        v2 = version2.split(".")
        v1n = [int(x) for x in v1 if int(x) > 0]
        v2n = [int(x) for x in v2 if int(x) > 0]
        minLen = min(len(v1n), len(v2n))
        for i in range(0, minLen):
            if v1n[i] > v2n[i]:
                return 1
            if v1n[i] < v2n[i]:
                return -1
        if len(v1n) > len(v2n):
            return 1
        if len(v1n) < len(v2n):
            return -1
        return 0