题解 | #牛牛学数列3#
牛牛学数列3
https://www.nowcoder.com/practice/f65c726d081c4160a9356eabf0dc21d9
#include <stdio.h>
int main() {
int n = 0;
scanf("%d", &n);
int i = 0, flag = 1, tem = 1;
float sum = 0.0f, result = 0.0f;
for (i = 1; i <= n; i++) {
sum += flag * tem;
result += 1.0 / (sum);
flag = -flag;
tem += 2;
}
printf("%.3f", result);
return 0;
}
