题解 | #字符串排序#

import re
input  = input()
xl = 'abcdefghijklmnopqrstuvwxyz'
# 正则提取所有的字母
reg = r'[a-zA-Z]+'
zm = ''.join(re.findall(reg, input))
sorted_zm = []
# 暴力排序
for one_zm in xl:
    for item in zm:
        if item.lower() == one_zm:
            sorted_zm.append(item)
# 输出字母时从上面拍好的序列中拿即可
for item in input:
    if item.isupper() or item.islower():
        print(sorted_zm.pop(0),end='')
    else:
        print(item,end='')