题解 | #删除链表的节点#

/*
 * function ListNode(x){
 *   this.val = x;
 *   this.next = null;
 * }
 */
/**
 * 代码中的类名、方法名、参数名已经指定，请勿修改，直接返回方法规定的值即可
 *
 * 
 * @param head ListNode类 
 * @param val int整型 
 * @return ListNode类
 */
function deleteNode(head, val) {
    // write code here
    let cur = head
    let pre = null
    if (cur.val === val) { return head = head.next }
    while (cur.val !== val) {
        pre = cur
        cur = cur.next
    }
    pre.next = cur.next
    return head
}
module.exports = {
    deleteNode: deleteNode
};