题解 | #小乐乐改数字#
小乐乐改数字
https://www.nowcoder.com/practice/fcd30aac9c4f4028b23919a0c649824d
#include <stdio.h>
#include<math.h>
int main() {
int n = 0, tem = 0, sum = 0, i = 0;
scanf("%d", &n);
while (n) //n的值为0时循环结束
{
tem = n % 10; //取个位的数值
if (tem % 2 == 0)
sum = sum + 0 * pow(10, i++);
else
sum = sum + 1 * pow(10, i++);
n /= 10; //把个位数删掉,即十进制右移一位
}
printf("%d", sum);
return 0;
}
