题解 | #牛牛的计划#
牛牛的计划
https://www.nowcoder.com/practice/cf956ceef9f84f7393a0b7284fdbf95a
#include <stdio.h>
int main() {
int y = 0, m = 0, d = 0, y1 = 0, m1 = 0, d1 = 0;
scanf("%d%d%d%d%d%d", &y, &m, &d, &y1, &m1, &d1);
if (y1 > y)
printf("yes");
else if (y1 == y)
{
if (m1 > m)
printf("yes");
else if (m1 == m)
{
if (d1 >= d)
printf("yes");
else
printf("no");
}
else
printf("no");
}
else
printf("no");
return 0;
}
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