题解 | #从单向链表中删除指定值的节点#
从单向链表中删除指定值的节点
https://www.nowcoder.com/practice/f96cd47e812842269058d483a11ced4f
total = list(map(int, input().strip().split()))
delete = total[-1]
result = [total[1]]
total = total[2:-1]
for i in range(0, len(total), 2):
result.insert(result.index(total[i+1])+1, total[i])
for i in result:
if i == delete:
result.remove(i)
print(*result)
）。