题解 | #扫雷#

#include <iostream>
using namespace std;

int main() {
    int n, m;
    cin >> n >> m;
    char mat[n][m];
    for (int i = 0; i < n; ++i)
    {
        for (int j = 0; j < m; ++j)
        {
            cin >> mat[i][j];
        }

    }
    char res[n][m];
    int direction[8][2] = {{-1, -1}, {-1, 0}, {-1, 1}, {0, -1}, {0, 1}, {1, -1}, {1, 0}, {1, 1}};
    char a;
    for (int i = 0; i < n; ++i)
    {
        for (int j = 0; j < m; ++j)
        {
            if ((*(*(mat + i) + j)) == '*')
                a = '*';
            else
            {
                a = '0';
                for (int k = 0; k < 8; k++)
                {
                    int ir = i + direction[k][0];
                    int jr = j + direction[k][1];
                    if (ir < 0 || ir >= n || jr < 0 || jr >= m)
                        continue;
                    else
                    {
                        if ((*(*(mat + ir) + jr)) == '*')
                            ++a;
                    }
                }
            }
            res[i][j] = a;
        }
    }

    for (int i = 0; i < n; ++i)
    {
        for (int j = 0; j < m; ++j)
        {
            cout << res[i][j];
        }
        cout << endl;
    }

}
// 64 位输出请用 printf("%lld")

按照题目要求写代码就好了