题解 | #求 1 - n 之间偶数的和#
求 1 - n 之间偶数的和
https://www.nowcoder.com/practice/03df7fa0950046a9ba564b4438f918a3
#include <iostream> using namespace std; int main() { int n; cin >> n; int sum = 0; sum=(n/2+1)*n/2; cout << sum << endl; return 0; }
用什么循环嘛!!!直接用公式他不香吗!!!