题解 | #2的n次方计算#
2的n次方计算
https://www.nowcoder.com/practice/35a1e8b18658411388bc1672439de1d9
#include <stdio.h> int main() { int num, num2 = 0; scanf("%d", &num); num2 = 2 << (num - 1); printf("%d", num2); return 0; }
2的n次方计算
https://www.nowcoder.com/practice/35a1e8b18658411388bc1672439de1d9
#include <stdio.h> int main() { int num, num2 = 0; scanf("%d", &num); num2 = 2 << (num - 1); printf("%d", num2); return 0; }
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