题解 | #二叉树的镜像#
二叉树的镜像
https://www.nowcoder.com/practice/a9d0ecbacef9410ca97463e4a5c83be7
/*
* function TreeNode(x) {
* this.val = x;
* this.left = null;
* this.right = null;
* }
*/
/**
* 代码中的类名、方法名、参数名已经指定,请勿修改,直接返回方法规定的值即可
*
*
* @param pRoot TreeNode类
* @return TreeNode类
*/
function Mirror(pRoot) {
return bfs(pRoot);
}
function dfs(root) {
if (!root) {
return root;
}
const temp = root.left;
root.left = root.right;
root.right = temp;
dfs(root.left);
dfs(root.right);
return root;
}
function bfs(root) {
if (!root) {
return root;
}
const queue = [root];
while (queue.length) {
const node = queue.shift();
const temp = node.left;
node.left = node.right;
node.right = temp;
node.left && queue.push(node.left);
node.right && queue.push(node.right);
}
return root;
}
module.exports = {
Mirror: Mirror,
};
