题解 | #二进制中1的个数#

#
# 代码中的类名、方法名、参数名已经指定，请勿修改，直接返回方法规定的值即可
#
# 
# @param n int整型 
# @return int整型
#
class Solution:
    def NumberOf1(self , n: int) -> int:
        # write code here
        if n >0:
            binnum =  bin(n)[2:].zfill(32)
        else:
            binnum = bin(n & 0xffffffff)[2:].zfill(32)
        print(binnum)
        return binnum.count('1')