题解 | #牛牛的三元组问题#
牛牛的三元组问题
https://www.nowcoder.com/practice/72c6d735fb1144a2ba162976a4510839
# # 代码中的类名、方法名、参数名已经指定,请勿修改,直接返回方法规定的值即可 # # # @param nums int整型一维数组 # @return int整型二维数组 # class Solution: def findTriplets(self, nums: List[int]) -> List[List[int]]: # write code here nums.sort() res = [] for i in range(len(nums) - 2): # Avoid duplicates if i > 0 and nums[i] == nums[i - 1]: continue left, right = i + 1, len(nums) - 1 while left < right: total = nums[i] + nums[left] + nums[right] if total == 0: res.append([nums[i], nums[left], nums[right]]) while left < right and nums[left] == nums[left + 1]: left += 1 while left < right and nums[right] == nums[right - 1]: right -= 1 left += 1 right -= 1 elif total < 0: left += 1 else: right -= 1 return res