题解 | #矩阵乘法# C++ 纯暴力
矩阵乘法
https://www.nowcoder.com/practice/ebe941260f8c4210aa8c17e99cbc663b
#include <iostream> #include <vector> using namespace std; int main() { int x, y, z; cin >> x >> y >> z; vector<vector<int>> ma(x, vector<int>(y, 0)); vector<vector<int>> mb(y, vector<int>(z, 0)); vector<vector<int>> res(x, vector<int>(z, 0)); for (int i = 0; i < x; i++) { for (int j = 0; j < y; j++) { cin >> ma[i][j]; } } for (int i = 0; i < y; i++) { for (int j = 0; j < z; j++) { cin >> mb[i][j]; } } for (int i = 0; i < x; i++) { for (int j = 0; j < z; j++) { for(int k=0;k<y;k++){ res[i][j] += ma[i][k] * mb[k][j]; } cout<<res[i][j] << " "; } cout<<endl; } return 0; } // 64 位输出请用 printf("%lld")