题解 | #牛群的最短路径#
牛群的最短路径
https://www.nowcoder.com/practice/c07472106bfe430b8e2f55125d817358
import java.util.*; /* * public class TreeNode { * int val = 0; * TreeNode left = null; * TreeNode right = null; * public TreeNode(int val) { * this.val = val; * } * } */ public class Solution { /** * 代码中的类名、方法名、参数名已经指定,请勿修改,直接返回方法规定的值即可 * * * @param root TreeNode类 * @return int整型 */ public int minDepth (TreeNode root) { // write code here if (root == null) return 0; minDepth = Integer.MAX_VALUE; levelOrder(root, 0); return minDepth; } private int minDepth; private void levelOrder(TreeNode root, int level) { if (root == null) return; level += 1; if (root.left == null && root.right == null) { minDepth = Math.min(level, minDepth); } levelOrder(root.left, level); levelOrder(root.right, level); } }
- 边界值处理
- 基于二叉树的层序遍历,查找到叶子节点,更新最短路径值
线性表基础 文章被收录于专栏
链表、递归、栈