题解 | #链表相加(二)#
链表相加(二)
https://www.nowcoder.com/practice/c56f6c70fb3f4849bc56e33ff2a50b6b
/** * struct ListNode { * int val; * struct ListNode *next; * ListNode(int x) : val(x), next(nullptr) {} * }; */ class Solution { public: /** * 代码中的类名、方法名、参数名已经指定,请勿修改,直接返回方法规定的值即可 * * * @param head1 ListNode类 * @param head2 ListNode类 * @return ListNode类 */ ListNode* addInList(ListNode* head1, ListNode* head2) { // write code here if (!head1) { return head2; } if (!head2) { return head1; } ListNode* new_head1 = reverseList(head1); ListNode* new_head2 = reverseList(head2); ListNode* res_head = new_head1; ListNode* pre_new_head1 = nullptr; int jinwei = 0; while (new_head1 && new_head2) { int sum = new_head1->val + new_head2->val + jinwei; jinwei = sum / 10; int yushu = sum % 10; new_head1->val = yushu; pre_new_head1 = new_head1; new_head1 = new_head1->next; new_head2 = new_head2->next; } if (new_head1) { while (new_head1) { int sum = new_head1->val + jinwei; jinwei = sum / 10; int yushu = sum % 10; new_head1->val = yushu; pre_new_head1 = new_head1; new_head1 = new_head1->next; } if (jinwei > 0) { pre_new_head1->next = new ListNode(jinwei); } } if (new_head2) { while (new_head2) { int sum = new_head2->val + jinwei; jinwei = sum / 10; int yushu = sum % 10; pre_new_head1->next = new ListNode(yushu); pre_new_head1 = pre_new_head1->next; new_head2 = new_head2->next; } if (jinwei > 0) { pre_new_head1->next = new ListNode(jinwei); } } return reverseList(res_head); } private: ListNode* reverseList(ListNode* head) { ListNode* pre = nullptr; ListNode* cur = head; while (cur) { ListNode* tmp = cur->next; cur->next = pre; pre = cur; cur = tmp; } return pre; } };