题解 | #字符串分隔#
字符串分隔
https://www.nowcoder.com/practice/d9162298cb5a437aad722fccccaae8a7
chars = input()
remainder = len(chars) % 8
if remainder:
chars += (8-remainder)*'0'
idx = 1
oct_group = ''
for v in chars:
if idx % 8:
oct_group += v
else:
oct_group += v
print(oct_group)
oct_group = ''
idx += 1
避免边界判断，直接在末尾加上（8-余数）个0
投递三一重工等公司7个岗位