题解 | #简单错误记录#
简单错误记录
https://www.nowcoder.com/practice/2baa6aba39214d6ea91a2e03dff3fbeb
import sys import re res = {} for line in sys.stdin: # path,id = line.strip().split(' ') path = line.strip().split('\\')[-1]##\\转译\ path = path[-20:]##截取字符串后20位 if path not in res: res[path]=0 res[path]+=1 for line in list(res.keys())[-8:]:##字典的索引方式,key转化为list之后进行索引 path,id = line.strip().split(' ') print(path,id,res[line])