题解 | #链表内指定区间反转#
链表内指定区间反转
https://www.nowcoder.com/practice/b58434e200a648c589ca2063f1faf58c
# class ListNode:
# def __init__(self, x):
# self.val = x
# self.next = None
#
# 代码中的类名、方法名、参数名已经指定,请勿修改,直接返回方法规定的值即可
#
#
# @param head ListNode类
# @param m int整型
# @param n int整型
# @return ListNode类
#
class Solution:
def reverseBetween(self , head: ListNode, m: int, n: int) -> ListNode:
if m == n:
return head
tmp_head = ListNode(-1) # 添加一个头,防止m=1,最后去掉
tmp_head.next = head
break_point = tmp_head
for i in range(m-1):
break_point = break_point.next # 断点
new_tail = break_point.next # 反转区间的新尾部
cur = new_tail # 指针、
per = cur.next
for i in range(n-m): # 需要n-m次反转
tmp = per.next
per.next = cur
cur = per
per = tmp
new_tail.next = per
break_point.next = cur
head = tmp_head.next
return head
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