题解 | #字符串变形#
字符串变形
https://www.nowcoder.com/practice/c3120c1c1bc44ad986259c0cf0f0b80e
# # 代码中的类名、方法名、参数名已经指定,请勿修改,直接返回方法规定的值即可 # # # @param s string字符串 # @param n int整型 # @return string字符串 # class Solution: def trans(self, s: str, n: int) -> str: # write code here strs = s.split(" ") strtemp = [] for i in range(len(strs)): # strtemp.append(''.join(reversed(strs[i]))) strtemp.append(strs[i][::-1]) ss = " ".join(strtemp) sss = ss[::-1] ssss = sss.swapcase() print(ssss) return ssss