题解 | #质数因子#
质数因子
https://www.nowcoder.com/practice/196534628ca6490ebce2e336b47b3607
const readline = require('readline') const rl = readline.createInterface({ input: process.stdin, output: process.stdout }) rl.on('line', (input) => { let target = Number(input) const result = [] // i*i大于target 证明只剩target一个质因子 // 因为这种情况下 target/i一定小于i 而小于i的质数因子在前面已经遍历过 for (let i = 2; i * i <= target; i++) { while (target % i === 0) { target /= i result.push(i) } } if (target > 1) result.push(target) console.log(result.join(' ')) })