题解 | #Johnson Counter#

Johnson Counter

https://www.nowcoder.com/practice/7ee6e9ed687c40c3981d7586a65bc22d

`timescale 1ns/1ns

module JC_counter(
   input                clk ,
   input                rst_n,
 
   output reg [3:0]     Q  
);

always@(posedge clk or negedge rst_n)
    if(!rst_n)
        Q   <=  4'd0;
    else 
        Q   <=  {~Q[0],Q[3:1]};

endmodule

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