题解 | #反转链表#
反转链表
https://www.nowcoder.com/practice/75e878df47f24fdc9dc3e400ec6058ca
import java.util.*; import java.lang.*; class ListNode { int val; ListNode next; public ListNode(int val) { this.val = val; } } public class Solution { /** * 代码中的类名、方法名、参数名已经指定,请勿修改,直接返回方法规定的值即可 * * * @param head ListNode类 * @return ListNode类 */ public ListNode ReverseList (ListNode head) { Stack<ListNode> stack = new Stack<>(); //把链表节点全部摘掉放到栈中 while (head != null) { stack.push(head); head = head.next; } if (stack.isEmpty()) return null; ListNode node = stack.pop(); ListNode dummy = node; //栈中的结点全部出栈,然后重新连成一个新的链表 while (!stack.isEmpty()) { ListNode tempNode = stack.pop(); node.next = tempNode; node = node.next; } //最后一个结点就是反转前的头结点,一定要让他的next //等于空,否则会构成环 node.next = null; return dummy; } }