题解 | #数组过滤#
数组过滤
https://www.nowcoder.com/practice/46d607f9bf64458daa8798339a7336d0
{"html":"<!DOCTYPE html>\r\n<html lang=\"en\">\r\n <head>\r\n <meta charset=\"UTF-8\">\r\n </head>\r\n <body>\r\n <select name=\"\" id=\"\">\r\n <option value=\"0\">请选择价格范围</option>\r\n <option value=\"1\"><100</option>\r\n <option value=\"2\">100~500</option>\r\n <option value=\"3\">>500</option>\r\n </select>\r\n <ul>\r\n <li>牛客logo马克杯</li>\r\n <li>无盖星空杯</li>\r\n <li>老式茶杯</li>\r\n <li>欧式印花杯</li>\r\n </ul>\r\n\r\n <script>\r\n var cups = [\r\n { type: 1, price: 100, color: 'black', sales: 60, name: '牛客logo马克杯' },\r\n { type: 2, price: 40, color: 'blue', sales: 100, name: '无盖星空杯' },\r\n { type: 4, price: 60, color: 'green', sales: 200, name: '老式茶杯' },\r\n { type: 3, price: 50, color: 'green', sales: 600, name: '欧式印花杯' }\r\n ]\r\n var select = document.querySelector('select');\r\n var ul = document.querySelector('ul');\r\n // 补全代码\r\n let obj = {\r\n 0:()=>[].concat(cups),\r\n 1:()=>cups.filter(item=>item.sales<100),\r\n 2:()=>cups.filter(item=>item.sales>=100&&item.sales<=500),\r\n 3:()=>cups.filter(item=>item.sales>500)\r\n }\r\n select.onchange = function(e){\r\n let srr = obj[select.value]();\r\n let len = srr.length;\r\n if(!len)return;\r\n let fragment = document.createDocumentFragment();\r\n for(let i = 0; i<len;i++){\r\n let li = document.createElement('li');\r\n li.innerText = srr[i].name;\r\n fragment.appendChild(li)\r\n }\r\n ul.innerHTML = '';\r\n ul.appendChild(fragment)\r\n \r\n }\r\n </script>\r\n </body>\r\n</html>","css":"/* html, body {\\n\\twidth: 100%;\\n\\theight: 100%;\\n\\tmargin: 0;\\n\\tpadding: 0;\\n} */","js":"// 请在这里输入代码"}
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