题解 | #判断是不是完全二叉树#
判断是不是完全二叉树
https://www.nowcoder.com/practice/8daa4dff9e36409abba2adbe413d6fae
# class TreeNode:
# def __init__(self, x):
# self.val = x
# self.left = None
# self.right = None
#
# 代码中的类名、方法名、参数名已经指定,请勿修改,直接返回方法规定的值即可
#
#
# @param root TreeNode类
# @return bool布尔型
#
class Solution:
def isCompleteTree(self , root: TreeNode) -> bool:
# write code here
list_tree = [root]
find = False
while list_tree:
t = []
for i in list_tree:
if not find :
if i.left != None :
t.append(i.left)
if i.right != None:
t.append(i.right)
else:
find = True
else:
if i.right != None:
return False
find = True
else:
if i.left != None or i.right != None:
return False
list_tree = t
return True
原始一点点的解法 文章被收录于专栏
尽量不借助面向对象的思想,自己去实习具体过程