题解 | #每个人的累计搜索点击数排名#

每个人的累计搜索点击数排名

https://www.nowcoder.com/practice/e66514c25a814029995313962cd44d62

select * from (select *,rank()over(order by search_num desc) as search_rank,rank()over(order by click_num desc) as click_rank from
(select uid,(case when search_num>0 then search_num else 0 end) as search_num,(case when click_num>0 then click_num else 0 end) as click_num from
(select uid,count(event_time) as search_num from search_log_tb group by uid) t1
left join
(select uid,count(event_time) as click_num from click_log_tb group by uid) t2 using(uid)) t3 
) t4 where search_rank<=3 or click_rank<=3

全部评论

相关推荐

10-11 17:30
湖南大学 C++
我已成为0offer的糕手:羡慕
点赞 评论 收藏
分享
评论
点赞
收藏
分享
牛客网
牛客企业服务