题解 | #字符串排序#
字符串排序
https://www.nowcoder.com/practice/5190a1db6f4f4ddb92fd9c365c944584
s = input()
s = list(s)
len_s = len(s)
i = 0
while i < len_s:
if 'a'<= s[i]<= 'z' or 'A'<= s[i] <= 'Z' :
t = i
j = i+1
while j < len_s:
if 'a'<= s[j]<= 'z' or 'A'<= s[j] <= 'Z' :
if s[t].upper() > s[j].upper():
s[t],s[j] = s[j],s[t]
t = j
j += 1
len_s -= 1
i = -1
i += 1
print(''.join(s))
原始一点点的解法 文章被收录于专栏
尽量不借助面向对象的思想，自己去实习具体过程
