题解 | #删除有序链表中重复的元素-II#

class Solution {
public:
    ListNode* deleteDuplicates(ListNode* head) {
        if(!head) return head;
        ListNode *res=new ListNode(-1);
        res->next=head;
        ListNode *cur=res;
        while(cur->next&&cur->next->next){
            if(cur->next->val==cur->next->next->val){
                int tmp=cur->next->val;
                while(cur->next->val==tmp&&cur->next!=NULL){  
                    cur->next=cur->next->next;

                }
            }

            else 
                cur=cur->next;
        }
        return res->next;
        }
    };