题解 | #蛇形矩阵#

n=int(input())
first_row=[(nn+1)*(nn+2)//2 for nn in range(n)] 
for i in range(n):
    for j in range(n-i):
        print(first_row[i+j]-i,end=' ') # 使用i+j作为索引
    print('')