题解 | #用优先编码器①实现键盘编码电路#

module key_encoder(
      input      [9:0]         S_n   ,         
 
      output reg [3:0]         L     ,
      output reg               GS
);

wire [3:0]out1;

encoder_0 encoder_0_inst
(
   .I_n({S_n[8:0]}),
   
   .Y_n (out1)  
);

always@(*)
    if (S_n[9] == 1'b0)
        L <= 4'd9;
    else if (out1 == 4'b1110)
        L <= 4'd0;
    else if (out1 == 4'b1101)
        L <= 4'd1;
    else if (out1 == 4'b1100)
        L <= 4'd2;
    else if (out1 == 4'b1011)
        L <= 4'd3;
    else if (out1 == 4'b1010)
        L <= 4'd4;
    else if (out1 == 4'b1001)
        L <= 4'd5;
    else if (out1 == 4'b1000)
        L <= 4'd6;
    else if (out1 == 4'b0111)
        L <= 4'd7;
    else if (out1 == 4'b0110)
        L <= 4'd8;

always@(*)           //着GS就很迷茫，但是这样子写是对的，我也不知道是咋碰对的QAQ
    if (out1 == 4'b1110)
        GS <= 1'b1;
    else if (out1 == 4'b1111)
        GS <= 1'b0;
    else 
        GS <= 1'b1;

endmodule