题解 | #时间转换#
时间转换
https://www.nowcoder.com/practice/c4ae7bcac7f9491b8be82ee516a94899
#include <stdio.h>
int main()
{
int seconds = 0;
scanf("%d",&seconds);
int a = seconds/3600;
int b = seconds%3600/60;
int c = seconds%3600%60;
if(0<seconds && seconds<100000000)
{
printf("%d %d %d",a,b,c);
}
return 0;
}
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