题解 | #人民币转换#

人民币转换

https://www.nowcoder.com/practice/00ffd656b9604d1998e966d555005a4b

import java.util.Scanner;


public class Main {
    public static void main(String[] args) {
        Scanner in = new Scanner(System.in);
        while (in.hasNextDouble()) { 
            System.out.println(f(in.nextDouble()));
        }
    }

   public static String f(double d) {
        String temp = d + "";
        String content = "人民币";
        double c = Double.parseDouble(temp.substring(0, temp.indexOf(".") + 1));
        if (c < 10000 && c >= 1) {
            content += e9999(c) + "元";
        } else if (c > 10000){
            content += getExtend(c) + "元";
        }
        double c2 = Double.parseDouble(temp.substring(temp.indexOf(".")));
        content +=  el(c2);
        return content;
    }

    public static String getExtend(double d) {
        if (d < 10000) return "";
        String[] dict = {"亿", "万"};
        double base = 1 * 10000 * 10000d;
        String content = "";
        int hindx = 0;
        while (hindx < 2) {
            double n = (int) (d / base);
            double c = n % base;
            if (c != 0) {
                if (hindx == 1) {
                    double save = d % base;
                    if (save == 0) {
                        content += e9999(c) + dict[hindx];
                    } else {
                        if (save < 1000) {
                            content += e9999(c) + dict[hindx] + "零" + e999(save);
                        } else {
                            content += e9999(c) + dict[hindx] + e9999(save);
                        }
                    }
                } else {
                    content += e9999(c) + dict[hindx];
                }
            }
            d %= base;
            base /= 10000;
            hindx++;
        }
        return content;
    }

    public static String e9999(double d) {
        if (d < 0 || d > 9999) return "";
        if (d <= 10) {
            return e9(d);
        }
        if (d > 10 && d < 100) {
            return e99(d);
        }
        if (d > 99 && d < 1000) {
            return e999(d);
        }
        double h = (int) (d / 1000);
        double m1 = (int) (d % 1000 / 100);
        double m2 = d % 100 / 10;
        double l = d % 10;
        if (m1 == 0) {
            return e9(h) + "仟零" + e99(d - h * 1000);
        } else {
            return e9(h) + "仟" + e999(d - h * 1000);
        }
    }

    public static String e999(double d) {
        if (d < 0 || d > 999) return "";
        if (d <= 10) {
            return e9(d);
        }
        if (d > 10 && d < 100) {
            return e99(d);
        }
        double h = (int) (d / 100);
        double m = (int) ((int) (d % 100) / 10);
        double l = d % 10;
        if (m == 0) {
            return e9(h) + "佰零" + e9(l);
        } else if (m == 1) {
            return e9(h) + "佰拾" + e9(l);
        } else {
            return e9(h) + "佰" + e9(m) + "拾" + e9(l);
        }
    }

    public static String e99(double d) {
        if (d < 0 || d > 99) {
            return "";
        }
        if (d > 0 && d <= 10) {
            return e9(d);
        }
        double c = (int) (d / 10);
        if (c == 1) {
            return "拾" + e9(d % 10);
        } else {
            return e9(c) + "拾" + e9(d % 10);
        }
    }

    public static String e9(double d) {
        if (d <= 0 || d > 10) return "";
        String[] names = {"零", "壹", "贰", "叁", "肆", "伍", "陆", "柒", "捌", "玖", "拾"};
        return names[(int) d];
    }

    public static String el(double d) {
        int a = (d + "").charAt(2) -'0';
        int b = 0;
        if ((d + "").length() == 4) {
            b = (d + "").charAt(3) -'0';
        }
        double one = a, two = b;
        if (one > 0 && two > 0) {
            return e9(one) + "角" + e9(two) + "分";
        } else if (one > 0 && two == 0) {
            return e9(one) + "角";
        } else if (one == 0 && two > 0) {
            return e9(two) + "分";
        } else {
            return "整";
        }
    }
}

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