题解 | #购物单#
购物单
https://www.nowcoder.com/practice/f9c6f980eeec43ef85be20755ddbeaf4
import Foundation var i = 0 var N = 0 var m = 0 var masterArr = [(sn:Int, price:Int, manyi:Int)]() var dict = [Int : [(price:Int, manyi:Int)]]() while let line = readLine() { let parts = line.split(separator: " ") if (parts[0] == "***") { break } if (i == 0) { N = Int(parts[0])! m = Int(parts[1])! } else if (Int(parts[2])! == 0) { // 主件 masterArr.append((sn:i - 1, price:Int(parts[0])!, manyi:Int(parts[1])!)) } else { var fujian:[(price:Int, manyi:Int)] = dict[Int(parts[2])! - 1] ?? [] fujian.append((price:Int(parts[0])!, manyi:Int(parts[1])!)) dict[Int(parts[2])! - 1] = fujian } i = i + 1 } //print(N) //print(m) //print(masterArr) //print(dict) var amount = masterArr.count var total = N var dp:[[Int]] = [[Int]](repeating: [Int](repeating: 0, count: total + 1), count: amount + 1) func calulate(total:Int, amount:Int) { // i 前i个,total:最大的钱数[0, tatal], dp:最大的满意度 for i in 0 ... amount { for j in 0 ... total { if ( i == 0) { dp[0][j] = 0 continue } if (j == 0) { dp[i][0] = 0 continue } var maxVal = 0 // 是否选择第i个 选择,不选择 // 不选择 dp[i][j] = dp[i - 1][j] maxVal = max(dp[i][j], maxVal) // 选择主件和附件,前i个,对应的下标就是 i - 1 var master = masterArr[i - 1] var fujians = dict[master.sn] ?? [] // 选择 有多种情况 // 只选主件、 选主件和附件1、选主件和附件2、选主件和附件1和2 if j - master.price >= 0 { dp[i][j] = dp[i - 1][j - master.price] + master.price * master.manyi maxVal = max(dp[i][j], maxVal) } if fujians.count == 1 { // 主件 + 附件1 var fujian1 = fujians[0] if (j - master.price - fujian1.price >= 0) { dp[i][j] = dp[i - 1][j - master.price - fujian1.price] + master.price * master.manyi + fujian1.price * fujian1.manyi maxVal = max(dp[i][j], maxVal) } } else if fujians.count == 2 { var fujian1 = fujians[0] var fujian2 = fujians[1] // 主件 + 附件1 if (j - master.price - fujian1.price >= 0) { dp[i][j] = dp[i - 1][j - master.price - fujian1.price] + master.price * master.manyi + fujian1.price * fujian1.manyi maxVal = max(dp[i][j], maxVal) } // 主件 + 附件2 if (j - master.price - fujian2.price >= 0) { dp[i][j] = dp[i - 1][j - master.price - fujian2.price] + master.price * master.manyi + fujian2.price * fujian2.manyi maxVal = max(dp[i][j], maxVal) } // 主件 + 附件1 + 附件2 if (j - master.price - fujian1.price - fujian2.price >= 0) { dp[i][j] = dp[i - 1][j - master.price - fujian1.price - fujian2.price] + master.price * master.manyi + fujian1.price * fujian1.manyi + fujian2.price * fujian2.manyi maxVal = max(dp[i][j], maxVal) } } dp[i][j] = maxVal } } } calulate(total: total, amount: amount) print(dp[amount][total])#华为OD的机试题目不容易啊#