题解 | #skew数#
skew数
https://www.nowcoder.com/practice/5928127cc6604129923346e955e75984
#include <iostream>
#include <string>
#include <cmath>
using namespace std;
int main() {
string str;
while (getline(cin, str)) {
int num = 0;
for(int i = 0; i < str.length(); i ++){
num += (str[i]-'0') * (pow(2, str.length()-i) -1);
}
cout << num << endl;
}
return 0;
}
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