题解 | #牛牛逆序输出#
牛牛逆序输出
https://www.nowcoder.com/practice/d981181ce18e4cce945fdf52daf037a1
#include <stdio.h>
int main() {
int n = 0;
int sum = 0;
scanf("%d", &n);
while (n)
{
sum = n % 10 + sum;
if (n < 10)
{
break;
}
sum *= 10;
n /= 10;
}
printf("%d", sum);
return 0;
}
