题解 | #从单向链表中删除指定值的节点#

tmp=list(map(int,input().split()))
n,head,deleting=tmp[0],tmp[1],tmp[-1]
cur,pre,l=[],[],[head]
for i in range(2,len(tmp)-1,2):
    cur.append(tmp[i])
for i in range(3,len(tmp)-1,2):
    pre.append(tmp[i])

for i in range(len(pre)):
    l.insert(l.index(pre[i])+1,cur[i])

l.pop(l.index(deleting))
for val in l:
    print(val,end=" ")