题解 | #简单计算器#

#include <stdio.h>

int main() {
    double a,b;
    char c;
    scanf("%lf%c%lf",&a,&c,&b);
    switch (c) {
        case '+':
            printf("%.4lf+%.4lf=%.4lf",a,b,a+b);
            break;  
        case '-':
            printf("%.4lf-%.4lf=%.4lf",a,b,a-b);
            break;
        case '*':
            printf("%.4lf*%.4lf=%.4lf",a,b,a*b);
            break;
        case '/':
            if (b == 0.0) {
                printf("Wrong!Division by zero!");
            }else {
                printf("%.4lf/%.4lf=%.4lf",a,b,a/b); 
            } 
            break;
        default:printf("Invalid operation!");
        break;
    }  
    return 0;
}