题解 | #二叉树的镜像#

/**
 * struct TreeNode {
 *	int val;
 *	struct TreeNode *left;
 *	struct TreeNode *right;
 * };
 */
/**
 * 代码中的类名、方法名、参数名已经指定，请勿修改，直接返回方法规定的值即可
 *
 * 
 * @param pRoot TreeNode类 
 * @return TreeNode类
 */
 void Mirroring(struct TreeNode* pRoot ) {
    struct TreeNode* p;
    p=pRoot->left;
    pRoot->left=pRoot->right;
    pRoot->right=p;
    if(pRoot->left)
    Mirroring(pRoot->left);
    if(pRoot->right)
    Mirroring(pRoot->right);
 }
struct TreeNode* Mirror(struct TreeNode* pRoot ) {
    // write code here
    if(pRoot!=NULL)
    Mirroring(pRoot);
    return pRoot;
}