题解 | #高精度整数加法#

const rl = require("readline").createInterface({ input: process.stdin });
var iter = rl[Symbol.asyncIterator]();
const readline = async () => (await iter.next()).value;
let lines = [];
void (async function () {
    // Write your code here
    while ((line = await readline())) {
        lines.push(line);
        if (lines.length === 2) {
            getResult(lines);
        }
    }
})();

function getResult(lines) {
    let short = lines[0].split("").map(Number);
    let long = lines[1].split("").map(Number);
    if (short.length > long.length) {
        let temp = short;
        short = long;
        long = temp;
    }
    short.unshift(...new Array(long.length - short.length).fill(Number(0)));
    // console.log(short)
    let result = [];
    let c = 0;
    while (long.length) {
        let r = long.pop() + short.pop() + c;
        result.unshift(r % 10);
        c = parseInt(r / 10);
        if (long.length === 0) {
            result.unshift(c);
            break;
        }
    }
    while (result[0] === 0) {
        result.shift();
    }
    if(result.length===0){
        result=[0]
    }
    console.log(result.join(""));
}

思路就是：将两个字符串转成数值，短的那段前边补足0至和长字符长度相等。然后按照加法运算法则将结果计入数组，最后将数组前空余的0去掉