题解 | #高精度整数加法#
高精度整数加法
https://www.nowcoder.com/practice/49e772ab08994a96980f9618892e55b6
const rl = require("readline").createInterface({ input: process.stdin });
var iter = rl[Symbol.asyncIterator]();
const readline = async () => (await iter.next()).value;
let lines = [];
void (async function () {
// Write your code here
while ((line = await readline())) {
lines.push(line);
if (lines.length === 2) {
getResult(lines);
}
}
})();
function getResult(lines) {
let short = lines[0].split("").map(Number);
let long = lines[1].split("").map(Number);
if (short.length > long.length) {
let temp = short;
short = long;
long = temp;
}
short.unshift(...new Array(long.length - short.length).fill(Number(0)));
// console.log(short)
let result = [];
let c = 0;
while (long.length) {
let r = long.pop() + short.pop() + c;
result.unshift(r % 10);
c = parseInt(r / 10);
if (long.length === 0) {
result.unshift(c);
break;
}
}
while (result[0] === 0) {
result.shift();
}
if(result.length===0){
result=[0]
}
console.log(result.join(""));
}
思路就是：将两个字符串转成数值，短的那段前边补足0至和长字符长度相等。然后按照加法运算法则将结果计入数组，最后将数组前空余的0去掉
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