题解 | #二叉树的后序遍历#

二叉树的后序遍历

https://www.nowcoder.com/practice/1291064f4d5d4bdeaefbf0dd47d78541?tpId=196&tqId=39373&rp=1&ru=/exam/oj&qru=/exam/oj&sourceUrl=%2Fexam%2Foj%3Fdifficulty%3D2%26page%3D1%26pageSize%3D50%26search%3D%26tab%3D%25E7%25AE%2597%25E6%25B3%2595%25E7%25AF%2587%26topicId%3D196&difficulty=2&judgeStatus=undefined&tags=5051&title=

# class TreeNode:
#     def __init__(self, x):
#         self.val = x
#         self.left = None
#         self.right = None
#
# 代码中的类名、方法名、参数名已经指定,请勿修改,直接返回方法规定的值即可
#
# 
# @param root TreeNode类 
# @return int整型一维数组
#
class Solution:
    def postorderTraversal(self , root: TreeNode) -> List[int]:
        # write code here
        if not root:
            return []

        f=[]
        f+=self.postorderTraversal(root.left)+self.postorderTraversal(root.right)+[root.val]
        return f

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