题解 | #有重复项数字的全排列#
有重复项数字的全排列
https://www.nowcoder.com/practice/a43a2b986ef34843ac4fdd9159b69863
# # 代码中的类名、方法名、参数名已经指定,请勿修改,直接返回方法规定的值即可 # # # @param num int整型一维数组 # @return int整型二维数组 # class Solution: def search(self,left,has): if len(left)==0: return [has] thisres = [] for i in range(len(left)): newleft = left[:i]+left[i+1:] searchres = self.search(newleft,has+[left[i]]) thisres += searchres return thisres def permuteUnique(self , num: List[int]) -> List[List[int]]: # write code here allres = self.search(num,[]) newres = [] for i in allres: if i not in newres: newres.append(i) allres = sorted(newres) return allres