题解 | #牛牛逆序输出#

fn reverse_num(num: i32) -> i32 {
    let mut reversed = 0;
    let mut n = num;
    while n != 0 {
        reversed = reversed * 10 + n % 10;
        n /= 10;
    }
    reversed
}

fn main() {
    let mut num = String::new();
    
    std::io::stdin().read_line(&mut num).unwrap();

    let num: i32 = num.trim().parse().unwrap();
    let reversed = reverse_num(num);
    println!("{}", reversed);
}