题解 | #二进制中1的个数#

public class Solution {
    public int NumberOf1(int n) {
        int num = 0 ;
        int n2 = n;
        if (n < 0) {
            n2 = -1 * n2;//负数取余为负数去符号后的正数取余
        }
        if (n2 % 2 == 1) {
            num ++;
        }
        while (n != 0) {
            n = n >>> 1;//无符号右移
            if (n % 2 == 1) {
                num ++;
            }
        }
        return num;
    }
}