题解 | #公共子串计算#
公共子串计算
https://www.nowcoder.com/practice/98dc82c094e043ccb7e0570e5342dd1b
a,b=input(),input()
res=''
for i in range(len(a)):
for j in range(i,len(a)):
if a[i:j+1] in b and j+1-i>len(res):
res=a[i:j+1]
print(len(res))
