题解 | #计算斐波那契数最小差值#

import java.util.Scanner;

// 注意类名必须为 Main, 不要有任何 package xxx 信息
public class Main {
    public static void main(String[] args) {
        Scanner in = new Scanner(System.in);
        // 注意 hasNext 和 hasNextLine 的区别
        while (in.hasNextInt()) { // 注意 while 处理多个 case
            int a = in.nextInt();


            if (a == 0) {
                System.out.println(0);
                continue;
            }

            int n = Math.max(6, a);

            int[] feibo = new int[n];

            feibo[0] = 0;
            feibo[1] = 1;
            int min = Math.min(Math.abs(a - feibo[1]), Math.abs(a - feibo[0]));
            for (int i = 2; i < n; i++) {
                feibo[i] = feibo[i - 1] + feibo[i - 2];
                min = Math.min(min, Math.abs(a - feibo[i]));
            }
            System.out.println(min);
        }
    }
}