题解 | #牛牛的短信#
牛牛的短信
https://www.nowcoder.com/practice/435c9e2bf4f84bee99b82ce84e95b0b7
#include <stdio.h>
int main() {
int n = 0;
while (1 == scanf("%d", &n))
{
int word = 0;
double sum = 0.0;
for (int i = 0; i < n; i++)
{
scanf("%d", &word);
if (word < 60)
{
sum += 0.1;
}
else
{
sum += 0.2;
}
}
printf("%.1lf", sum);
}
return 0;
}
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