题解 | #在旋转过的有序数组中寻找目标值#
在旋转过的有序数组中寻找目标值
https://www.nowcoder.com/practice/87c0e7abcbda41e7963660fa7d020995
package main
/**
* 代码中的类名、方法名、参数名已经指定,请勿修改,直接返回方法规定的值即可
*
*
* @param nums int整型一维数组
* @param target int整型
* @return int整型
*/
func search(nums []int, target int) int {
l := 0
r := len(nums) - 1
for l <= r {
mid := (l + r) / 2
if mid == 0 {
if mid+1 < len(nums) && nums[mid] < nums[mid+1] {
r = mid - 1
} else {
l = mid + 1
}
} else {
if nums[mid]-nums[0] > 0 {
l = mid + 1
} else {
r = mid - 1
}
}
}
ll := 0
rr := l - 1
for ll <= rr {
mid := (ll + rr) / 2
if nums[mid] == target {
return mid
} else if nums[mid] < target {
ll = mid + 1
} else {
rr = mid - 1
}
}
ll = l
rr = len(nums) - 1
for ll <= rr {
mid := (ll + rr) / 2
if nums[mid] == target {
return mid
} else if nums[mid] < target {
ll = mid + 1
} else {
rr = mid - 1
}
}
return -1
// write code here
}

