题解 | #在旋转过的有序数组中寻找目标值#

在旋转过的有序数组中寻找目标值

https://www.nowcoder.com/practice/87c0e7abcbda41e7963660fa7d020995

package main

/**
 * 代码中的类名、方法名、参数名已经指定,请勿修改,直接返回方法规定的值即可
 *
 * 
 * @param nums int整型一维数组 
 * @param target int整型 
 * @return int整型
*/
func search(nums []int, target int) int {
	l := 0
	r := len(nums) - 1
	for l <= r {
		mid := (l + r) / 2
		if mid == 0 {
			if mid+1 < len(nums) && nums[mid] < nums[mid+1] {
				r = mid - 1
			} else {
				l = mid + 1
			}
		} else {
			if nums[mid]-nums[0] > 0 {
				l = mid + 1
			} else {
				r = mid - 1
			}
		}

	}
	ll := 0
	rr := l - 1
	for ll <= rr {
		mid := (ll + rr) / 2
		if nums[mid] == target {
			return mid
		} else if nums[mid] < target {
			ll = mid + 1
		} else {
			rr = mid - 1
		}
	}
	ll = l
	rr = len(nums) - 1
	for ll <= rr {
		mid := (ll + rr) / 2
		if nums[mid] == target {
			return mid
		} else if nums[mid] < target {
			ll = mid + 1
		} else {
			rr = mid - 1
		}
	}
	return -1
	// write code here
}

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