题解 | #简单密码#

package main

import (
	"fmt"
	"os"
    "bufio"
)

func transform(s string) string {
    m := make(map[byte]byte, 0)
    m['a'] = '2'; m['b'] = '2'; m['c'] = '2'
    m['d'] = '3'; m['e'] = '3'; m['f'] = '3'
    m['g'] = '4'; m['h'] = '4'; m['i'] = '4'
    m['j'] = '5'; m['k'] = '5'; m['l'] = '5'
    m['m'] = '6'; m['n'] = '6'; m['o'] = '6'
    m['p'] = '7'; m['q'] = '7'; m['r'] = '7'; m['s'] = '7'
    m['t'] = '8'; m['u'] = '8'; m['v'] = '8'
    m['w'] = '9'; m['x'] = '9'; m['y'] = '9'; m['z'] = '9'

    size := len(s)
    sb := make([]byte, size)

    for i:=0; i<size; i++ {
        ch := s[i]
        if 'a' <= s[i] && s[i] <= 'z' {
            ch = m[s[i]]
        } else if 'A' <= s[i] && s[i] <= 'Z' {
            ch = byte(s[i] + 32)
            if ch == 'z' {
                ch = 'a'
            } else {
                ch = ch + 1
            }
        } else {
            ch = s[i]
        }

        sb[i] = ch
    }

    return string(sb)
}

func main() {
    var s string

    inputReader := bufio.NewReader(os.Stdin)
    line, _, _ := inputReader.ReadLine()

    s = string(line)
    // fmt.Println(s)

    fmt.Println(transform(s))
}

// 本题输入一行字符串，所以使用：inputReader.ReadLine()