题解 | #数值的整数次方#

class Solution {
public:
    double Power(double base, int exponent) 
    {
        if(exponent == 0)
            return 1;
        if(base == 0)
            return 0;

        double ret = 1;
        int e = exponent < 0 ? -exponent : exponent;

        while(e)
        {
            ret *= base;
            e--;
        }

        if(exponent < 0)
            return 1/ret;
        else
         return ret;
    }
};